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8x^2+12x-176=0
a = 8; b = 12; c = -176;
Δ = b2-4ac
Δ = 122-4·8·(-176)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-76}{2*8}=\frac{-88}{16} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+76}{2*8}=\frac{64}{16} =4 $
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